Rezolvatii in Q Ecuatiile Clasa a 7 a Exercitiul 13 A)

Răspuns:
S = {-11}
Explicație pas cu pas:
[tex]\displaystyle{ \frac{7}{x-3} = \frac{8}{x-5} }[/tex]
[tex]\displaystyle{ 7 \cdot (x - 5) = 8 \cdot (x- 3) }[/tex]
[tex]\displaystyle{ 7x - 7 \cdot 5 = 8x - 8 \cdot 3 }[/tex]
[tex]\displaystyle{ 7x - 35 = 8x - 24 }[/tex]
[tex]\displaystyle{ -35 = x - 24 }[/tex]
[tex]\displaystyle{ x = -35 + 24 }[/tex]
[tex]\boxed{x=-11}[/tex]