Răspuns:
a) [tex]\frac{x+3}{4} +\frac{2x+1}{3}=\frac{x-3}{6}+\frac{3x+1}{12}[/tex] /·12
3x+9+8x+4=2x-6+3x+1
6x=-18 /:6 x=-3
c) [tex]\frac{3x-7}{20} -\frac{1}{10}=\frac{2-x}{5}+\frac{x-3}{4}[/tex] /·20
3x-7-2=8-4x+5x-15
4x=2 /:2 [tex]x=\frac{1}{2}[/tex]
e) [tex]\frac{2}{5} (x-3)+\frac{4x+6}{15} =\frac{2x+7}{10}-1\frac{1}{30}[/tex]
[tex]\frac{2x-6}{5}+\frac{4x+6}{15} =\frac{2x+7}{10}-\frac{31}{30}[/tex] /:30
12x-36+8x+12=6x+21-31
14x=14 /:14 x=1
Explicație pas cu pas:
