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va rog sa ma ajutati...!​ logaritmul

Va Rog Sa Ma Ajutati Logaritmul class=

Răspuns :

deci am făcut și doua metodă

Vezi imaginea NICUBEJENARIU
Vezi imaginea NICUBEJENARIU

 

[tex]\displaystyle\bf\\c)\\8^x=2~~~(Logaritmam~ecuatia.)\\\\log_2(8^x)=log_2(2)\\\\x\cdot log_2(8)=log_2(2)\\\\x\cdot log_2(2^3)=log_2(2^1)\\\\x\cdot3=1\\\\3x=1\\\\\boxed{\bf x=\frac{1}{3}}\\\\\\d)\\5^x=6~~~(Logaritmam~ecuatia.)\\\\log_5(5^x)=log_5(6)\\\\x\cdot log_5(5)=log_5(6)\\\\x\cdot 1=log_5(6)\\\\\boxed{\bf x=log_5(6)}~~(unde~log_5(6)~este~un~numar~real)\\\\\\[/tex]

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[tex]\displaystyle\bf\\e)\\4^{x+1}=5~~~(Logaritmam~ecuatia.)\\\\log_4(4^{x+1})=log_4(5)\\\\(x+1)\cdot log_4(4)=log_4(5)\\\\(x+1)\cdot 1=log_4(5)\\\\x+1=log_4(5)\\\\\boxed{\bf x=log_4(5)-1}~~(unde~log_4(5)~este~un~numar~real)[/tex]