Răspuns:
1.
[tex]1 + \frac{1}{4} > \frac{a}{4} [/tex]
=>
[tex]1 + \frac{1}{4} = \frac{4 + 1} {4 } = \frac{5}{4} [/tex]
=>
[tex] \frac{5}{4} > \frac{4}{4} [/tex]
[tex] \frac{5}{4} > \frac{3}{4} [/tex]
[tex] \frac{5}{4} > \frac{2}{4} [/tex]
[tex] \frac{5}{4} > \frac{1}{4} [/tex]
[tex] \frac{5}{4} > \frac{0}{4} [/tex]
=> "a" poate fi= 4;3;2;1;0.
(Eu am inlocuit "1+ 1/4" cu "5/4",pentru că acesta este rezultatul sau,tu daca vrei poti sa il lasi "1+1/4")
2.
[tex] \frac{9}{5} - \frac{a}{5} \leqslant \frac{3}{5} [/tex]
[tex] \frac{9}{5} - \frac{6}{5} = \frac{3}{5} \leqslant \frac{3}{5} [/tex]
[tex] \frac{9}{5} - \frac{7}{5} = \frac{2}{5} \leqslant \frac{3}{5} [/tex]
[tex] \frac{9}{5} - \frac{8}{5} = \frac{1}{5} \leqslant \frac{3}{5} [/tex]
[tex] \frac{9}{5} - \frac{9}{5} = 0 \leqslant \frac{3}{5} [/tex]
=> "a" poate fi =6;7;8;9
