Notez:
x- fotbal
y- handbal
z- patinaj
Fac un sistem de 3 ecuatii cu 3 necunoscute:
y=2/6 •x = 1/3 •x = x/3
z= 10+2/8 • (y+x) = 10 + (x+y)/4
x+y+z=210
z= 10+1/4 • (x/3+x) = 10+ x/3
x+x/3 + z = 210 | •3
3x+x+3z= 630
4x+3z=630
Avem acum un sistem de 2 ecuatii cu 2 necunoscute:
z= 10+x/3
4x+3z=630
Avem:
4x+ 3•(10+x/3)=630
4x+30+x=630
5x=600 |:5
x=120
Deci footbal=120 elevi
Handbal avem: y=1/3•x= 1/3 • 120 = 40 elevi
Patinaj avem: z= 10+1/4(120+40)=10+40=50 elevi