Răspuns:
Explicație:
200g Na2 CO3
200g NaCl
200g Fe2O3
nr. moli
n= m : M
MNa2CO3= 2.23 + 12 + 3.16 =106------> 106g/moli
n= 200g : 106g/moli= 1,88 moli Na2CO3
MNaCl= 23 + 35.5=58,5-------> 58,5g/moli
n= 200 g : 58,5g/moli=3,42 moli NaCl
MFe2O3= 2.56 + 3.18= 160----> 160g/moli
n= 200g : 160g/moli = 1,25 moli Fe2 O3