Răspuns:
Explicație pas cu pas:
[tex]\large \bf 2\sqrt{3x} \cdot 2\sqrt{3x} = [/tex]
[tex]\large \bf 2\cdot 2\cdot \sqrt{3x}\cdot \sqrt{3x} =[/tex]
[tex]\large \bf 4\cdot (\sqrt{3x})^{2}=[/tex]
[tex]\large \bf 4\cdot 3x = \pink{\boxed{\bf 12 x}}[/tex]
[tex]\large \bf 2\sqrt{3}x \cdot 2\sqrt{3}x = [/tex]
[tex]\large \bf 2\cdot 2\cdot \sqrt{3}\cdot \sqrt{3} \cdot x \cdot x =[/tex]
[tex]\large \bf 4\cdot (\sqrt{3})^{2}\cdot x^{2}=[/tex]
[tex]\large \bf 4\cdot 3\cdot x^{2} = \red{\boxed{\bf 12 x^{2}}}[/tex]
#copaceibrainly
