Răspuns:
M,NH3= 17g/mol=17Kg/kmol
n(niu)= m/M= 10,2kg/17kg/kmol=0.6kmol=600mol NH3
1mol.......6,023x10²³molec(numarul lui Avogadro)
600mol...........x
x=3613x10²³molec=3,6x10²⁶molec
ro(densitatea)=m/v---> m= 100mlx0,8ml=80g
M,C3H6O= 58g/mol
n(niu)= 80/58mol=1,38mol
1mol..........6,023x10²³molec
1,38mol............x
x=8,3x10²³molec
Explicație: