Salut,
[tex]\left(log_3(3x)\right)\ '=\dfrac{(3x)\ '}{3x\cdot ln3}=\dfrac{3}{3x\cdot ln3}=\dfrac{1}{x\cdot ln3}.[/tex]
[tex](ln(x+1))\ '=\dfrac{(x+1)\ '}{x+1}=\dfrac{1}{x+1}.\\\\(ln(3x^2))\ '=\dfrac{(3x^2)\ '}{3x^2}=\dfrac{6x}{3x^2}=\dfrac{2}{x}.[/tex]
Ai înțeles ?
Green eyes.
