[tex]\bf \Bigg[5-2,(6) \Bigg] : \Bigg[0,5 \cdot \dfrac{1}{3} + 0,(4) \cdot 0,25\Bigg] \cdot \dfrac{3}{4}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf \Bigg(5-\dfrac{26-2}{9} \Bigg) : \Bigg(\dfrac{5}{10}\cdot \dfrac{1}{3} + \dfrac{4}{9} \cdot \dfrac{25}{100} \Bigg) \cdot \dfrac{3}{4}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf \Bigg( 5-\dfrac{24}{9}\Bigg) : \Bigg(\dfrac{1}{2} \cdot \dfrac{1}{3}+\dfrac{4}{9} \cdot \dfrac{1}{4} \Bigg) \cdot \dfrac{3}{4}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf\Bigg( 5-\dfrac{8}{3} \Bigg) : \Bigg(\dfrac{1}{6}+\dfrac{1}{9} \Bigg) \cdot \dfrac{3}{4}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf \dfrac{15-8}{3} : \dfrac{3+2}{18} \cdot \dfrac{3}{4}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf \dfrac{7}{3} : \dfrac{5}{18} \cdot \dfrac{3}{4} = \dfrac{7}{3} \cdot \dfrac{18}{5} \cdot \dfrac{3}{4} = \red{ \boxed{\bf \dfrac{63}{10}}}[/tex]
[tex]\bf \;[/tex]
[tex]\bf \Bigg[ 1,3(5) : 6\dfrac{7}{9}-0,1\Bigg] \cdot 6\dfrac{2}{3} =[/tex]
[tex]\bf \;[/tex]
[tex]\bf \Bigg( \dfrac{135-13}{90} : 6\dfrac{7}{9} - \dfrac{1}{10} \Bigg) \cdot 6 \dfrac{2}{3}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf \Bigg( \dfrac{122}{90} : \dfrac{6 \cdot 9 +7}{9} - \dfrac{1}{10} \Bigg) \cdot \dfrac{6 \cdot 3 +2}{3}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf \Bigg( \dfrac{122}{90} : \dfrac{61}{9} - \dfrac{1}{10} \Bigg) \cdot \dfrac{20}{3}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf \Bigg( \dfrac{122}{90} \cdot \dfrac{9}{61} - \dfrac{1}{10} \Bigg) \cdot \dfrac{20}{3}=[/tex]
[tex]\bf \;[/tex]
[tex]\bf \Bigg(\dfrac{2}{10}-\dfrac{1}{10}\Bigg) \cdot \dfrac{20}{3}= \dfrac{1}{10} \cdot \dfrac{20}{3}= \red {\boxed{\bf \dfrac{2}{3} }}[/tex]
[tex]\bf \;[/tex]
[tex]\green {\rm \#copaceibrainly }[/tex]
