Răspuns:
BC = 6
Explicație pas cu pas:
Salutare!
Pentru a rezolva exercitiul trebuie sa folosim Teorema Sinusului:
[tex]\frac{AB}{sin C} = \frac{BC}{sin A} = \frac{AC}{sin B}[/tex]
[tex]Din \ \ \frac{AB}{sin C} = \frac{BC}{sin A} = > \frac{2\sqrt{3} }{sin30} = \frac{BC}{sin60} \\\\\frac{2\sqrt{3} }{\frac{1}{2}} =\frac{BC}{\frac{\sqrt{3}}{2} } \\\\\\4\sqrt{3} = \frac{2BC}{\sqrt{3}} => BC = \frac{4\sqrt{3} *\sqrt{3} }{2} = \frac{4*3}{2} = \frac{12}{2} = 6\\\\BC = 6[/tex]
Succes!
