Răspuns:
[tex]2\sqrt{3} =\sqrt{2^2*3} =\sqrt{4*3} =\sqrt{12} \\
\\
3\sqrt{2} =\sqrt{3^2*2} =\sqrt{9*2} =\sqrt{18} \\
\\
-5\sqrt{6} =-\sqrt{5^2*6} =-\sqrt{25*6} =-\sqrt{150} \\
\\
-4\sqrt{7} =-\sqrt{4^2*7} =-\sqrt{16*7} =-\sqrt{112} \\
\\
6\sqrt{5} =\sqrt{6^2*5} =\sqrt{36*5} =\sqrt{180} \\
\\
7\sqrt{3} =\sqrt{7^2*3} =\sqrt{49*3} =\sqrt{147} [/tex]
