decât d.si e.
Dau coroana

Răspuns:
Explicație pas cu pas:
[tex] \bf d) \: [ {3}^{3} \times 3 + {2}^{45} \div {2}^{42} + ( {3}^{5} )^{6} \div {3}^{29} + {9}^{0} ] \div 31[/tex]
[tex] \bf [ {3}^{3} \times {3}^{1} + {2}^{45} \div {2}^{42} + {3}^{(5 \times 6)} \div {3}^{29} + {9}^{0} ] \div 31[/tex]
[tex] \bf [ {3}^{(3 + 1)} + {2}^{(45 - 42)} + {3}^{30} \div {3}^{29} + {9}^{0} ] \div 31[/tex]
[tex] \bf [ {3}^{4} + {2}^{3} + {3}^{(30 - 29)} + {9}^{0} ] \div 31[/tex]
[tex] \bf ( {3}^{4} + {2}^{3} + {3}^{1} + {9}^{0} ) \div 31[/tex]
[tex] \bf (81 + 8 + 3 + 1) \div 31[/tex]
[tex] \bf (89 + 3 + 1) \div 31[/tex]
[tex] \bf (92 + 1) \div 31[/tex]
[tex] \bf 93 \div 31 = \red{ \boxed{3} } [/tex]
[tex] \bf e) \: ( {2}^{8} + {9}^{2} + {5}^{6} + {36}^{2} ) \div ( {0}^{6} + {4}^{4} + {3}^{4} + {25}^{3} + {6}^{4} )[/tex]
[tex] \bf (256 + 81 + 15625 + 1296) \div (0 + 256 + 81 + 15625 + 1296)[/tex]
[tex] \bf (337 + 15625 + 1296) \div (256 + 81 + 15625 + 1296)[/tex]
[tex] \bf (15962 + 1296) \div (337 + 15625 + 1296)[/tex]
[tex] \bf 17258 \div (15962 + 1296)[/tex]
[tex] \bf 17258 \div 17258 = \red{ \boxed{1} } [/tex]