Răspuns,explicație pas cu pas:
1.
[tex]=x^{2} +2x*3+3^{2} =\\=x^{2} +6x+9[/tex]
2.
[tex]=(2y)x^{3} -3*(2y)^{2} *1+3*2y*1^{2} -1^{3} =\\=8y^{3} -3*4y^{2} *1+3*2y*1-1=\\=8y^{3}-12y^{2} +6y-1[/tex]
3.
[tex]=(3a)^{2} -2^{2} =\\=9a^{2}-4[/tex]
4.
[tex]=y*3y-4y+7*3y-7*4\\=3y^{2} -4y+21y-28=\\=3y^{2} +17y-28[/tex]
5.
[tex]=5x-10-(16+8x+x^{2} )=\\=5x-10-16-8x-x^{2} =\\=-3x-26-x^{2} =\\=-x^{2} -3x-26[/tex]
6.
[tex]=x^{3} -3^{3} =\\=(x-3)*(x^{2} +x*3+3^{2} )=\\=(x-3)*(x^{2} +3x+9)[/tex]
Succes! (am scris direct raspunsul)
