Poate ajuta cineva la ex 7?

7. ΔABC-isoscel
[AB]≡[AC]
M∈[BC]
[AM]≡[ME]
a) AB≡AC≡CE
AM≡ME
M⊥BC⇒BM=MC ⇒ΔABM≡ΔMCE
b) ΔACE
AC≡CE ⇒ΔACE-isoscel