Răspuns:
date necesare
miu,NaOH= 40g/mol
miu,H2SO4= 98g/mol
c= mdx100/ms
-Calculez masa si moli NaOH pur
p=m,px100/m,i---> m,p= 400x40/100g= 160g
niu=m/miu= 160/40mol=4molNaOH
-calculez moli si masa acid sulfuric ,din ecuatia chimica
2mol..............1mol
2NaOH + H2SO4---> Na2SO4+ 2H2O
4mol.................x
x=niu= 2molH2SO4
m= niuxmiu=2x98g= 196gH2SO4
-ACEASTA este masa dizolvata in solutia data->calculez masa solutiei
ms= mdx100/c= 196x100/49g= 400g
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Explicație:
