Răspuns:
Explicație pas cu pas:
Exercițiul 2
[tex]\bf \{120-2\cdot[14+5\cdot(x-3)]\}:4=8~~~\bigg|\cdot4[/tex]
[tex]\bf 120-2\cdot[14+5\cdot(x-3)]=8\cdot4[/tex]
[tex]\bf 120-2\cdot[14+5\cdot(x-3)]=32[/tex]
[tex]\bf 120-32 = 2\cdot[14+5\cdot(x-3)][/tex]
[tex]\bf 88 = 2\cdot[14+5\cdot(x-3)]~~~\bigg|:2[/tex]
[tex]\bf 14+5\cdot(x-3) = 44[/tex]
[tex]\bf 14+5\cdot(x-3) = 44-14[/tex]
[tex]\bf 5\cdot(x-3) = 30~~~\bigg|:5[/tex]
[tex]\bf x-3 = 6[/tex]
[tex]\bf x = 6+3[/tex]
[tex]\red{\boxed{~\bf x=9~}}[/tex]
Exercițiul 3
a = 2 · 3³ · 6⁵
a = 2 · 3³ · 2⁵ · 3⁵
a = 2⁵⁺¹ · 3³⁺⁵
a = 2⁶ · 3⁸
a = (2³)² · (3⁴)²
a = (2³ · 3⁴)² → pătrat perfect
Exercițiul 4
a) 3²⁰ si 2³⁰
3²⁰ = (3²)¹⁰ = 9¹⁰
2³⁰ = (2³)¹⁰ = 8¹⁰
9¹⁰ > 8¹⁰ ⇒ 3²⁰ > 2³⁰
==pav38==
