Răspuns:
a.
m(AOB)=2x
m(BOC)=3x
m(COD)=4x-60
m(DOA)=4x+30
Fiind unghiuri in jurul unui punct, suma lor este de 360 => 2x+3x+4x-60+4x+30=360=>
13x-30=360 => 13x=390 => x=30 grade
m(AOB)=2x=2*30=60 grade
m(BOC)=3x=3*30=90 grade
m(COD)=4x-60=4*30-60=60 grade
m(DOA)=4x+30=4*30+30=150 grade
b.
[OM-bisect < AOB => m(AOM)=m(MOB)=30 grade
[ON-bisect < BOC => m(BON)=m(NOC)=45 grade
=> m(MON)=m(MOB)+m(BON)=30+45=75 grade
꧁Sper ca te-am ajutat!꧂
