[tex]\it =\Big(-\dfrac{11}{18}-\dfrac{20}{9}\cdot\dfrac{-2}{10}\Big)^3\cdot\dfrac{-12}{10}=\Big(-\dfrac{11}{18}+\dfrac{^{2)}4}{\ 9}\Big)^3\cdot\dfrac{-12}{10}=\\ \\ \\ =\Big(-\dfrac{3^{(3}}{18}\Big)^3\cdot\dfrac{-12^{(2}}{10}=\Big(-\dfrac{1}{6}\Big)^3\cdot\dfrac{-6}{5}=-\dfrac{1}{6\cdot6\cdot6}\cdot\dfrac{-6}{5}=\dfrac{1}{36\cdot5}=\dfrac{1}{180}[/tex]
